1/3(x-4)^2=-4

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Solution for 1/3(x-4)^2=-4 equation: 


x in (-oo:+oo)

(1/3)*(x-4)^2 = -4 // + 4

(1/3)*(x-4)^2+4 = 0

1/3*(x-4)^2+4 = 0

1/3*(x-4)^2+4 = 0

1/3*x^2-8/3*x+28/3 = 0

1/3*x^2-8/3*x+28/3 = 0

1/3*(x^2-8*x+28) = 0

x^2-8*x+28 = 0

DELTA = (-8)^2-(1*4*28)

DELTA = -48

DELTA < 0

1/3 = 0

1/3 = 0

1/3 = 0 // * 3

1 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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